如何用SQL比较两行的值?

2022-01-25 00:00:00 sql compare select row sqlite

我正在使用 sqlite 数据库.我的表架构是

I am using sqlite database. My table schema is

CREATE TABLE performance(area TEXT, name TEXT, score INTEGER, dt TEXT)

表格中的内容是这样的:

The content in the table is like this:

uk|josh|4|2013-11-04 20:00
ca|josh|2|2013-11-05 20:00
us|josh|6|2013-11-05 20:00
uk|andy|5|2013-11-04 20:00
us|andy|1|2013-11-05 20:00
uk|sara|9|2013-11-05 20:00
ca|sara|7|2013-11-06 20:00   
ca|sara|2|2013-11-06 20:00

我使用下面的sql语句来选择name及其对应的按name和dt分组的score总和.

I used the following sql statement to select name and its corresponding sum of score grouping by name and dt.

select name, sum(score), dt from performance group by name, dt;

我明白了

josh|4|2013-11-04 20:00
josh|8|2013-11-05 20:00
andy|5|2013-11-04 20:00
andy|1|2013-11-05 20:00
sara|9|2013-11-05 20:00
sara|9|2013-11-06 20:00

现在我想扩展我的查询，以便 sql 语句可以搜索其分数总和在不同时间(dt)没有变化的那个.在这种情况下，输出应该是这样的:

Now I want to expand my query so that the sql statement can search that whose sum of score didn't change at different time(dt). In this case the output should be like:

sara|9|2013-11-05 20:00
sara|9|2013-11-06 20:00

这样的sql怎么写?

推荐答案

这可以通过自(反)join来实现:

This can be achieved by a self (anti) join:

SELECT a.*
FROM   (SELECT name, dt, SUM(score) as sum_score 
        FROM   performance 
        GROUP BY name, dt) a
JOIN   (SELECT name, dt, SUM(score) as sum_score
        FROM   performance 
        GROUP BY name, dt) b
ON     a.name = b.name AND a.sum_score = b.sum_score AND a.dt < b.dt

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