在 mysql 查询中枢轴
我们有下面给出的查询,输出如下:
We have the query which is given below and the output is as follows:
mysql> select count(1) as cnt ,card.Program_ID program_id ,fd.load_type load_type ,
-> if(fd.load_type =0 ,concat('unload_cl_proram_',card.program_id) ,concat('load_cl_proram_',card.program_id)) as load_desc
-> from transaction_log_details fd inner join card card
-> on fd.Card_ID = card.Card_ID where card.Date_Created>='2011-01-01' and card.Date_Created<='2011-06-01'
-> and card.Program_ID in (4,5,6,7,8)
-> group by card.Program_ID,fd.load_type;
+-----+------------+-----------+--------------------+
| cnt | program_id | load_type | load_desc |
+-----+------------+-----------+--------------------+
| 5 | 4 | 0 | unload_cl_proram_4 |
| 14 | 4 | 1 | load_cl_proram_4 |
| 55 | 5 | 0 | unload_cl_proram_5 |
| 91 | 5 | 1 | load_cl_proram_5 |
| 13 | 6 | 0 | unload_cl_proram_6 |
| 29 | 6 | 1 | load_cl_proram_6 |
| 175 | 7 | 0 | unload_cl_proram_7 |
| 411 | 7 | 1 | load_cl_proram_7 |
| 61 | 8 | 0 | unload_cl_proram_8 |
| 161 | 8 | 1 | load_cl_proram_8 |
+-----+------------+-----------+--------------------+
10 rows in set (0.00 sec)
Now we want the output as follows: (some thing like pivot).
unload_cl_proram_4 load_cl_proram_4 unload_cl_proram_5 load_cl_proram_5 unload_cl_proram_6 load_cl_proram_6 unload_cl_proram_7 load_cl_proram_7 unload_cl_proram_8 load_cl_proram_8
5 14 55 91 13 29 175 411 61 161
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类似问题 - SQL 查询使用 CASE 旋转列当
http://www.sqlshare.com/pivot-using-the-case-statement_524.aspx(视频)
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