在 SQL 中将列转换为行
我需要编写一个查询,它接受行并将其转换为列 - 这是我的表:
I need to write a query which takes rows and converts it into columns - here's my table:
Count fname lname id
-----------------------------
1 abc def 20
2 pqr 20
3 abc xyz 20
4 xyz xyz 20
1 abc def 21
1 pqr xyz 22
2 abc abc 22
这是我试图产生的输出:
This is the output I'm trying to produce:
id fname lname fname lname fname lname fname lname
-------------------------------------------------------------
20 abc def pqr NULL abc xyz xyz xyz
21 abc def NULL NULL NULL NULL NULL NULL
22 abc abc NULL NULL NULL NULL NULL NULL
每个 id 的 count 最大值为 4.我使用的是 Oracle 9i.
The max value of count for each id is 4. I'm using Oracle 9i.
推荐答案
这是另一个你可能会遇到的问题.我喜欢@ThinkJet,但不确定解码成本是多少(如果多于或少于以下.
Here's another one you might have some luck with. I like @ThinkJet's but not sure how much decode costs (if more or less than this below.
SELECT
T1.ID,
T1.fname,
T1.lname,
T2.fname,
T2.lname,
T3.fname,
T3.lname,
T4.fname,
T4.lname
FROM
table T1
LEFT JOIN
table T2
ON
T1.ID = T2.ID
AND T2.count = 2
LEFT JOIN
table T3
ON
T1.ID = T3.ID
AND T3.count = 3
LEFT JOIN
table T4
ON
T1.ID = T4.ID
AND T4.count = 4
WHERE
T1.count = 1
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