引用同一个表作为 UPDATE 的目标和 MySql 中的数据源

2022-01-17 00:00:00 sql-update subquery mysql

我想对我的本地数据库进行更新，我会在其中使某些字段与表中存在的另一个字段具有相同的值.

I wanted to make an update against my local database where I'd make some of the fields have the same value as another field present in the table.

我想出了这个查询:

$wpdb->prepare(
    "
    UPDATE wp_usermeta meta
    SET meta.meta_value = (
      SELECT usermeta.meta_value
      FROM wp_usermeta usermeta
      WHERE usermeta.meta_key='nickname'
      AND usermeta.user_id = %d
    )
    WHERE meta.user_id = %d
    AND meta.meta_key='first_name'
    ",
    $userId[0],
    $userId[0]
)

查询将在 PHP 循环中运行，因此在每次迭代中 $userId 都会不同.查询是针对 WordPress 数据库运行的(但这应该与问题无关).

The query would be run in a PHP loop so on each iteration the $userId will be different. The query is run against WordPress database (but this should be irrelevant to the question).

我在尝试运行查询时收到以下错误:

I'm receiving the following error when attempting to run the query:

表 'meta' 被指定了两次，既作为 'UPDATE' 的目标，又作为单独的数据源

Table 'meta' is specified twice, both as a target for 'UPDATE' and as a separate source for data

我该如何解决这个问题?

How could I solve this problem?

推荐答案

一种方法是使用 join 代替:

One method is to use join instead:

UPDATE wp_usermeta meta JOIN
       wp_usermeta meta2
       on meta.user_id = meta2.user_id and
          meta2.meta_key = 'nickname'
SET meta.meta_value = meta2.meta_value
WHERE meta.user_id = %d AND meta.meta_key = 'first_name';

我可能会建议在 where 子句中添加一些内容，例如 meta.meta_value is not null，以防万一名字已被填充.但是，您似乎想复制该字段，这就是上面所做的.

I might suggest adding something to the where clause such as meta.meta_value is not null, just in case the first name is already populated. However, you seem to want to copy the field, which is what the above does.

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