使用另一个表中的数据更新一个表中的行，基于每个列中的一列相等

2022-01-17 00:00:00 sql-update sql oracle

更新许多行到一个表中基于每个列中的一列相等(user_id).

Update many rows into one table from another table based on one column in each being equal (user_id).

两个表都有一个 user_id 列.当user_id列相等时，需要将t2中的数据插入到t1中.

both tables have a user_id column. Need to insert data from t2 into t1 when the user_id column are equal.

提前感谢您提供的任何帮助.

Thank you in advance for any help offered.

推荐答案

update 
  table1 t1
set
  (
    t1.column1, 
    t1.column2
      ) = (
    select
      t2.column1, 
      t2.column2
    from
      table2  t2
    where
      t2.column1 = t1.column1
     )
    where exists (
      select 
        null
      from 
        table2 t2
      where 
        t2.column1 = t1.column1
      );

或者这个(如果 t2.column1 <=> t1.column1 是多对一并且其中任何一个都是好的):

Or this (if t2.column1 <=> t1.column1 are many to one and anyone of them is good):

update 
  table1 t1
set
  (
    t1.column1, 
    t1.column2
      ) = (
    select
      t2.column1, 
      t2.column2
    from
      table2  t2
    where
      t2.column1 = t1.column1
    and
      rownum = 1    
     )
    where exists (
      select 
        null
      from 
        table2 t2
      where 
        t2.column1 = t1.column1
      );

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