TypeError:“范围"对象不支持项目分配

2022-01-31 00:00:00 python python-3.x

问题描述

我正在查看一些 python 2.x 代码并试图将其转换为 py 3.x 但我被困在这一部分.谁能澄清什么是错的?

I was looking at some python 2.x code and attempted to translate it to py 3.x but I'm stuck on this section. Could anyone clarify what is wrong? 

import random

emails = {
    "x": "[REDACTED]@hotmail.com",
    "x2": "[REDACTED]@hotmail.com",
    "x3": "[REDACTED]@hotmail.com"
}

people = emails.keys()

#generate a number for everyone
allocations = range(len(people))
random.shuffle(allocations)

这是给出的错误:

TypeError: 'range' object does not support item assignment

解决方案

在 Python 3 中，range 返回一个惰性序列对象——它不返回一个列表.无法重新排列范围对象中的元素，因此无法对其进行混洗.

In Python 3, range returns a lazy sequence object - it does not return a list. There is no way to rearrange elements in a range object, so it cannot be shuffled.

在洗牌之前将其转换为列表.

Convert it to a list before shuffling.

allocations = list(range(len(people)))

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