TypeError:缺少 1 个必需的位置参数:'self'

2022-01-31 00:00:00 python python-3.x

问题描述

我无法克服错误:

Traceback (most recent call last):
  File "C:UsersDomDesktop	est	est.py", line 7, in <module>
    p = Pump.getPumps()
TypeError: getPumps() missing 1 required positional argument: 'self'

我检查了几个教程，但似乎与我的代码没有什么不同.我唯一能想到的是 Python 3.3 需要不同的语法.

I examined several tutorials but there doesn't seem to be anything different from my code. The only thing I can think of is that Python 3.3 requires different syntax.

class Pump:

    def __init__(self):
        print("init") # never prints

    def getPumps(self):
        # Open database connection
        # some stuff here that never gets executed because of error
        pass  # dummy code

p = Pump.getPumps()

print(p)

如果我理解正确，self 会自动传递给构造函数和方法.我在这里做错了什么?

If I understand correctly, self is passed to the constructor and methods automatically. What am I doing wrong here?

解决方案

这里需要实例化一个类实例.

You need to instantiate a class instance here.

使用

p = Pump()
p.getPumps()

小例子——

>>> class TestClass:
        def __init__(self):
            print("in init")
        def testFunc(self):
            print("in Test Func")


>>> testInstance = TestClass()
in init
>>> testInstance.testFunc()
in Test Func

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