MySQL查询选择表中时间值等于当前时间的字段
我想做的是每分钟运行一个程序.该程序使用 C 代码获取当前时间和日期,然后我尝试获取 MySQL 查询来比较数据库字段中的时间,以查看它是否与当前时间匹配.我只想在从 MySQL 中提取值时使用小时和分钟,而不是秒.我似乎无法让 MySQL 查询工作.
What I want to do is have a program run every minute. The program uses C code to get the current time and date and then I am trying to get a MySQL query to compare the time in the database field to see if it matches the current time. I only want to use the hour and minute when exctraing the value from MySQL and not the seconds. I can not seem to get the MySQL query to work.
注意代码中的%s是让C程序插入c代码生成的当前时间.
Note the %s in the code is for the C program to insert the current time generated by the c code.
这里是 MySQL:
SELECT active, type, date, time, action, command FROM `Alarm`
WHERE TIME_FORMAT('time', '%H:%i') = '%s'
当我在 snprintf 尝试插入时间变量之后打印查询时,我将其作为输出得到,它似乎试图将值插入 %i 而不是 %s,并且时间的格式是不工作:
WHen I print the query after snprintf trying to insert the time variable I get this as an output it seem that it is trying to insert the value into the %i and not the %s, and that the format for the time is not working:
SELECT alarm_active, alarm_category, alarm_date, alarm_time, alarm_action, alarm_command FROM Alarm
WHERE TIME_FORMAT(alarm_time, '%H:6297664') = '< F'
SELECT alarm_active, alarm_category, alarm_date, alarm_time, alarm_action, alarm_command FROM Alarm
WHERE TIME_FORMAT(alarm_time, '%H:6297664') = '<�F'
这是 C 代码:
char buffer[1024];
const char *query = "SELECT alarm_active, alarm_category, alarm_date, alarm_time, alarm_action, alarm_command FROM `Alarm` WHERE (alarm_time='%s')";
//const char *query = "SELECT active, type, date, time, action, command FROM `Alarm` WHERE active = '1'";
//Checking to see if connection to DB is succefful
if (mysql_query(conn, query) != 0)
{
fprintf(stderr, "%s
", mysql_error(conn));
exit(1);
} else {
if (snprintf(buffer, sizeof(buffer), query, current_time) >= sizeof(buffer))
{
printf("Issue with Buffer
");
exit (-1);
}
获取时间的其余代码:
char current_time [11];
time_t raw;
time(&raw);
struct tm *time_ptr;
time_ptr = localtime(&raw);
now with the "tm", you can format it to a buffer
char current_date[11];
char current_time [11];
strftime(current_date, sizeof(current_date), "%m/%d/%Y", time_ptr);
strftime(current_time, sizeof(current_time), "%H:%M", time_ptr);
推荐答案
你不需要 C 代码.你可以在数据库中做任何事情:
You don't need C code for this. You can do everything in the database:
SELECT active, type, date, time, action, command
FROM `Alarm`
WHERE TIME_FORMAT(time, '%H:%i') = TIME_FORMAT(now(), '%H:%i') and
date = curdate();
但是,我强烈建议您不要采用这种方法.您应该存储最后处理的记录的 ID(或至少是日期/时间).然后你应该选择从那时起的所有 id.
However, I strongly advise you not to take this approach. You should store the id (or at least the date/time) of the last record processed. Then you should select all ids since then.
您建议的方法很可能会在同一分钟内运行两次,或者错过一分钟.
Your suggested method has the significant possibility of running twice in the same minute, or missing a minute.
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