re.findall 行为怪异
问题描述
源字符串是:
# Python 3.4.3
s = r'abc123d, hello 3.1415926, this is my book'
这是我的模式:
pattern = r'-?[0-9]+(\.[0-9]*)?|-?\.[0-9]+'
但是，re.search 可以给我正确的结果:
however, re.search can give me correct result:
m = re.search(pattern, s)
print(m) # output: <_sre.SRE_Match object; span=(3, 6), match='123'>
re.findall 只是转储一个空列表:
re.findall just dump out an empty list:
L = re.findall(pattern, s)
print(L) # output: ['', '', '']
为什么不能 re.findall 给我预期的列表:
why can't re.findall give me the expected list:
['123', '3.1415926']
解决方案
s = r'abc123d, hello 3.1415926, this is my book'
print re.findall(r'-?[0-9]+(?:.[0-9]*)?|-?.[0-9]+',s)
您在使用原始模式时不需要转义两次.
You dont need to escape twice when you are using raw mode.
输出:['123', '3.1415926']
返回类型也是字符串的列表.如果您希望返回类型为 integers 和 floats，请使用 map
Also the return type will be a list of strings. If you want return type as integers and floats use map
import re,ast
s = r'abc123d, hello 3.1415926, this is my book'
print map(ast.literal_eval,re.findall(r'-?[0-9]+(?:.[0-9]*)?|-?.[0-9]+',s))
输出:[123, 3.1415926]
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