Oracle 错误“数据类型不一致:预期 CHAR 得到 LONG"

2021-12-30 00:00:00 sql oracle11g oracle

我正在尝试运行以下查询以查找包含给定关键字的视图:

I'm trying to run the following query to find views containing a given keyword:

select  *
from    ALL_VIEWS
where   OWNER = 'SALESDBA'
        and TEXT like '%rownum%';

我收到以下错误消息:

ORA-00932: inconsistent datatypes: expected CHAR got LONG
00932. 00000 -  "inconsistent datatypes: expected %s got %s"
*Cause:    
*Action:
Error at Line: 4 Column: 13

如果我只是从 ALL_VIEWS 中选择，那么我会在 TEXT 字段中看到查询 (TEXT).

if I just select from ALL_VIEWS than I see the query (TEXT) in the TEXT field.

我在这里做错了什么?

推荐答案

您的问题是 TEXT 是 LONG 类型 - 尽管 Oracle 很久很久以前就弃用了这种类型，但他们仍在自己的视图中使用它:-(

Your problem is that TEXT is of type LONG - although Oracle deprecated this type a long, long time ago, they're still using it in their own views :-(

要将 LONG 转换为(可搜索的)CLOB，您可以使用 TO_LOB() 函数(请参阅 TO_LOB() 的 Oracle 文档.

To convert a LONG to a (searchable) CLOB, you can use the TO_LOB() function (see Oracle documentation for TO_LOB().

不幸的是，这不适用于简单的 SELECT 语句.您必须创建一个中间表:

Unfortunately, this doesn't work for simple SELECT statements. You'll have to create an intermediary table:

create table search_all_views as 
select  av.owner, av.view_name, to_lob(text) as text_clob
from    ALL_VIEWS av;

然后，您可以使用该表进行搜索:

Then, you can search using that table:

select * 
from search_all_views
where text_clob like '%rownum%';

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