如何重命名 Oracle XMLTYPE 节点

2021-12-30 00:00:00 xml oracle11g oracle plsql xmltype

我在 PL/SQL 中有一个 XMLType，我需要重命名一些节点和一些值.例如:

I have an XMLType in PL/SQL and I need to rename some of the nodes and some of the values. For example:

<root>
   <fields>
        <a>foo</a>
        <b>bar</b>
   </fields>
</root>

我想把上面的变成这样:

I want to turn the above into this:

<root>
   <fields>
        <a>foo</a>
        <c>baz</c>
   </fields>
</root>

我知道我可以像这样更新值:

I know I can update the value like this:

SELECT UpdateXML(my_xml, '/root/fields/b/text()', 'baz')
  INTO my_xml_updated
  FROM DUAL;

结果是:

<root>
   <fields>
        <a>foo</a>
        <b>baz</b>
   </fields>
</root>

但是如何将节点名称从 更新为 (不影响节点的内容)?b>

But how can I update the node name from <b> to <c> (without affecting the contents of the node)?

推荐答案

一种选择是使用 XMLTRANSFORM 重命名节点.另见例如使用 XSLT 重命名节点.

One option is to use XMLTRANSFORM to rename a node. See also e.g. Rename nodes with XSLT.

with
xmldata as (select xmltype('<root>
  <fields>
    <a>foo</a>
    <b>bar</b>
  </fields>
</root>') val from dual),
stylesheet as (select '<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <!-- Identity transformation -->
  <xsl:template match="node()|@*">
    <xsl:copy>
      <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
  </xsl:template>
  <!-- Identity transformation overridden for element b -->
  <xsl:template match="b">
    <xsl:element name="c">
      <xsl:apply-templates select="node()|@*"/>
    </xsl:element>
  </xsl:template>
</xsl:stylesheet>' val from dual)
select xmltransform(x.val, s.val) from xmldata x, stylesheet s;

输出:

XMLTRANSFORM(X.VAL,S.VAL)
--------------------------------------------------------------------------------
<root>
  <fields>
    <a>foo</a>
    <c>bar</c>
  </fields>
</root>

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