如何生成字段等于“Dayofweek"、“weekofyear"的日期表?等；行等于从 2010-01-01 到 current_date 的日期

如何生成包含Dayofweek"、weekofyear"等字段的日期表；行等于从 2010-01-01 到 current_date 的日期如下图:

 Dayofweek Dayofmonth Dayofyear Weekofmonth Weekofyear 假期2010-01-01 6 1 1 1 1 是2010-01-02 7 2 2 1 1 否2010-01-03 1 3 3 1 1 否.....2019-03-31 1 31 90 6 14 N

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附言DayofWeek = 一周中的第几天，Sun = 1，Sat = 7Dayofmonth = 该月的第几天

 Holiday是一个标志，用于区分记录是否为公众假期

所以我需要做的第一步可能是创建从 2010-01-01 到 current_date 的记录，我想知道 hive 和 mssql 中的 while 循环会做什么?然后我准备好了专栏最后将它们结合起来.

我试过了

"声明@startdate日期声明@enddate 日期设置@startdate = '2010-01-01'设置@end_date = current_date而@start_date <=end_date开始DATEADD(DAY,1,@startdate)结尾"声明@startdate 日期声明@enddate 日期设置@startdate = '2010-01-01'设置@end_date = current_date而@start_date <=end_date开始DATEADD(DAY,1,@startdate)结尾Dayofweek Dayofmonth Dayofyear Weekofmonth Weekofyear 假期2010-01-01 6 1 1 1 1 是2010-01-02 7 2 2 1 1 否2010-01-03 1 3 3 1 1 否.....2019-03-31 1 31 90 6 14 N

解决方案

Hive 解决方案:

set hivevar:start_date=2010-01-01;--替换为您的开始日期设置 hivevar:end_date=current_date;--替换为您的结束日期与 date_range 作为(--此查询生成日期范围选择 date_add ('${hivevar:start_date}',s.i) 作为 dt从(选择posexplode(split(space(datediff(${hivevar:end_date}，'${hivevar:end_date}，'${hivevar:start_date}'))，''))作为(i，x))s),假期为(选择堆栈(5，--添加更多'01-01', '新年','01-21', '马丁路德金纪念日','02-18', '总统日','05-27', '阵亡将士纪念日','07-04', '独立日') as ( mtdt,holiday_name))选择 d.dt 作为日期，date_format(current_date,'u') 作为星期几，day(dt) 作为 dayofmonth，date_format(current_date,'D') 作为 dayofyear，date_format(current_date,'W') 作为 weekofmonth，weekofyear(dt) 作为 weekofyear，如果 h.mtdt 不为空，则 'Y' 否则 'N' 以假期结束，h.holiday_name从 date_range d在 substr(d.dt,6)= h.mtdt 上左加入假期 h;

添加更多假期.

How can i generate a Date table with fields like "Dayofweek", "weekofyear" etc ;and rows equals to date from 2010-01-01 till current_date like below:

             Dayofweek   Dayofmonth  Dayofyear Weekofmonth Weekofyear Holiday
2010-01-01       6           1            1          1          1        Y
2010-01-02       7           2            2          1          1        N
2010-01-03       1           3            3          1          1        N
.....
2019-03-31       1           31           90         6         14        N

P.S. DayofWeek = day num of the week, Sun = 1, Sat = 7 Dayofmonth = day num of the month

 Holiday is a flag to distinguish whether the records is a public holiday

So first step i need to do may be create records from 2010-01-01 till current_date, i wonder while loop in hive and mssql will do? Then I have the column ready Finally combine them.

I have tried

"Declare @startdate date
Declare @enddate date

set @startdate = '2010-01-01'
set @end_date = current_date

while @ start_date <=end_date
BEGIN
    DATEADD(DAY,1,@startdate)
END

"Declare @startdate date
Declare @enddate date

set @startdate = '2010-01-01'
set @end_date = current_date

while @ start_date <=end_date
BEGIN
    DATEADD(DAY,1,@startdate)
END

             Dayofweek   Dayofmonth  Dayofyear Weekofmonth Weekofyear Holiday
2010-01-01       6           1            1          1          1        Y
2010-01-02       7           2            2          1          1        N
2010-01-03       1           3            3          1          1        N
.....
2019-03-31       1           31           90         6         14        N

解决方案

Solution for Hive:

set hivevar:start_date=2010-01-01; --replace with your start_date
set hivevar:end_date=current_date; --replace with your end_date

with date_range as 
(--this query generates date range
select date_add ('${hivevar:start_date}',s.i) as dt 
  from ( select posexplode(split(space(datediff(${hivevar:end_date},'${hivevar:start_date}')),' ')) as (i,x) ) s
),

holiday as (
select stack(5, --add more
             '01-01', 'New Year',
             '01-21', 'Martin Luther King Day',
             '02-18', 'Presidents Day',
             '05-27', 'Memorial Day',
             '07-04', 'Independence Day'
        ) as ( mtdt,holiday_name)
) 

select d.dt                                 as date,
       date_format(current_date,'u')        as dayofweek,
       day(dt)                              as dayofmonth,
       date_format(current_date,'D')        as dayofyear,
       date_format(current_date,'W')        as weekofmonth,
       weekofyear(dt)                       as weekofyear, 
       case when h.mtdt is not null then 'Y' else 'N' end as Holiday,
       h.holiday_name
  from date_range d 
       left join holiday h on substr(d.dt,6)= h.mtdt
;

Add more holidays.