如何根据外键每行具有不同状态的状态从父表和子表中获取数据
我有 2 个具有外键关系的表.情况是我有一个 case
和一个 case
有很多 revision
并且每个 revision
都有自己的 状态
.如果仅更改外键表状态的特定行,我想获取父表数据和子数据
I have 2 tables with foreign key relationship. Situation is I have a case
and a case
have many revision
s and every revision
have its own status
. I want to get parent table data and child data if only specific row of foreign key table status is changed
表格案例
id case_no patient_name age
1 12564 abc 78
2 1256 lkj 63
3 125 bdhf 23
表格Case_Revisons
id case_id revison status
1 1 0 assesemnt
2 1 1 assesment
3 1 2 treatment
4 2 2 assesment
5 3 1 assesment
我想要的是来自 Case
和 Case Revisions
表的所有数据,其中状态为 treatment
What I want is all data all data from Case
and Case Revisions
table where status is treatment
我尝试了什么:
$data['treatment_setup_cases'] = MedicalPrimaryCases::with('primaryCaseNo')
->where('impression_type', 1)
->where('status', 'treatment-setup')
->get();
public function primaryCaseNo()
{
return $this->belongsTo(PrimaryCaseNo::class, 'primary_medical_case_id');
}
推荐答案
在此处使用连接:
$the_data_you_want = Case::join('case_revisions', 'case.id', '=', 'case_revisions.case_id')
->where('status', 'treatment')
->get();
PrimaryCaseNo
和 impression_type
在问题的解释中没有提到,所以我忽略了它们,如果需要,你可以改变它.
PrimaryCaseNo
and impression_type
were not mentioned in the explanation of the question so I ignored them, you can change this if necessary.
希望对你有帮助.
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