小于或等于 Oracle SQL
updated_date = 08-Jun-2010;
我有一个这样的查询
select * from asd whre updated_date <= todate('08-Jun-2010', 'dd-MM-yy');
但我没有得到任何结果.它仅适用于 todate
是 09-Jun-2010...
but I am not getting any results. it only works if todate
is 09-Jun-2010...
即我的 equalto
操作符工作不正常.
i.e. my equalto
operator is not working properly.
为什么会这样?
推荐答案
在 Oracle 中,DATE 是一个时间点.它总是有一个精确到秒的时间分量.todate('08-Jun-2010', 'dd-Mon-yyyy')
在 Oracle 中与 todate('08-Jun-2010 00:00:00', 'dd-Mon-yyyy hh24:mi:ss')
.因此,如果您选择截至该日期的行,您将不会在当天获得任何时间分量不等于 00:00
的行.
In Oracle a DATE is a point in time. It always has a time component with a precision to the second. todate('08-Jun-2010', 'dd-Mon-yyyy')
is in Oracle the same as todate('08-Jun-2010 00:00:00', 'dd-Mon-yyyy hh24:mi:ss')
. So if you select rows up to that date you won't get any row on that day with a time component not equal to 00:00
.
如果您想选择直到并包括 08-JUN-2010
的所有行,我建议使用:
If you want to select all the rows up to and including 08-JUN-2010
, I would suggest using:
< to_date('09-06-2010', 'dd-MM-yyyy')
或
<= to_date('08-06-2010 23:59:59', 'dd-MM-yyyy hh24:mi:ss')
注意 - 我更正了您的日期格式:如果您想使用缩写的月份名称,则需要使用 MON
.我建议改用 MM
,这样当有人更改其客户端设置 (NLS_DATE_LANGUAGE
) 时,您就不会出错.也更喜欢使用 YYYY
而不是 YY
.
Note - I corrected your date format: you need to use MON
if you want to use the abbreviated month name. I would suggest using MM
instead, so that you won't get error when someone changes its client settings (NLS_DATE_LANGUAGE
). Also prefer the use of YYYY
instead of YY
.
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