如何做一个函数来从 pl/sql 中的表中返回行类型?
我创建了这个函数,但是当我执行它时它返回一个错误!
I made this function but it return an error when i execute it!
create or replace function get_accounts
(Acc_id in Account1.account_id%Type)
return account1%rowtype
as
l_cust_record account1%rowtype;
begin
select * into l_cust_record from account1
where account_id=Acc_id;
return(l_cust_record);
end;
/
推荐答案
Oracle 设置:
CREATE TABLE account1 (
account_id INT,
name VARCHAR2(20)
);
INSERT INTO account1 VALUES ( 1, 'Bob' );
CREATE OR REPLACE FUNCTION get_accounts(
Acc_id IN Account1.account_id%TYPE
) RETURN account1%ROWTYPE
AS
l_cust_record account1%ROWTYPE;
BEGIN
SELECT *
INTO l_cust_record
FROM account1
WHERE account_id = Acc_id;
RETURN l_cust_record;
END;
/
PL/SQL 块:
DECLARE
r_acct ACCOUNT1%ROWTYPE;
BEGIN
r_acct := get_accounts( 1 );
DBMS_OUTPUT.PUT_LINE( r_acct.name );
END;
/
输出:
Bob
相关文章