将 to_char(myDate, 'DAY') 的结果与字符串进行比较时出现问题

2021-12-24 00:00:00 sql oracle11g oracle plsql

我一直试图找出可能是什么问题，但我只是运气不好，根本不了解这个问题.我有以下代码:

I have been trying to find what the issue might be but I am just out of luck and don't understand this problem at all.I have the following code:

CREATE OR REPLACE FUNCTION ckeckDay(dateC in date)
RETURN VARCHAR
IS
  day VARCHAR(15);
  checkFriday VARCHAR(1);
BEGIN
  checkFriday := 'N';
  day := to_char(dateC, 'DAY');
  IF day = 'FRIDAY' THEN
    checkFriday := 'Y';
  END IF;
  RETURN day;
END;
/

dateC 设置为 Friday(甚至通过返回 day 而不是 day 变量来测试它并返回 Friday.)但是IF 语句永远不会计算为真，即使 day 变量确实是星期五.任何想法如何解决这个问题.谢谢

the dateC is set to Friday (even tested it by returning day instead of the day variable and it returns Friday.) However the IF statement never evaluates to true even though the day variable is indeed Friday.Any ideas how to go around this issue.Thanks

推荐答案

这是因为 day 变量包含一个空白填充值.使用 trim 函数去除前导和尾随空格:

It is because day variable contains a blank padded value. Use trim function to get rid of leading and trailing spaces:

IF trim(day) = 'FRIDAY' THEN
  checkFriday := 'Y';
END IF;

并且请使用 VARCHAR2 数据类型作为字符串变量.不要使用VARCHAR.

And please use VARCHAR2 datatype for string variables. Do not use VARCHAR.

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