SQL 删除几乎重复的行
我有一个包含不幸数据的表,我正在尝试过滤掉一些数据.我确信 LName、FName 组合是唯一的,因为数据集小到可以验证.
I have a table that contains unfortuantely bad data and I'm trying to filter some out. I am sure that the LName, FName combonation is unique since the data set is small enough to verify.
LName, FName, Email
----- ----- -----
Smith Bob bsmith@example.com
Smith Bob NULL
Doe Jane NULL
White Don dwhite@example.com
我希望查询结果带回没有NULL电子邮件的重复"记录,但在没有重复时仍然带回NULL电子邮件.
I would like to have the query results bring back the "duplicate" record that does not have a NULL email, yet still bring back a NULL Email when there is not a duplicate.
例如
Smith Bob bsmith@example.com
Doe Jane NULL
White Don dwhite@example.com
我认为解决方案类似于Sql,按值删除重复行,但我真的不明白提问者的要求是否和我的一样.
I think the solution is similar to Sql, remove duplicate rows by value, but I don't really understand if the asker's requirements are the same as mine.
有什么建议吗?
谢谢
推荐答案
如果有任何非空值,这将删除空行.
This drops the null rows if there are any non null values.
SELECT lname
, fname
, MIN(email)
FROM YourTable
GROUP BY
lname
, fname
测试脚本
DECLARE @Test TABLE (
LName VARCHAR(32)
, FName VARCHAR(32)
, Email VARCHAR(32)
)
INSERT INTO @Test
SELECT 'Smith', 'Bob', 'bsmith@example.com'
UNION ALL SELECT 'Smith', 'Bob', 'NULL'
UNION ALL SELECT 'Doe', 'Jane', 'NULL'
UNION ALL SELECT 'White', 'Don', 'dwhite@example.com'
SELECT lname
, fname
, MIN(Email)
FROM @Test
GROUP BY
lname
, fname
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