ORA-01843 不是有效月份 - 比较日期
尝试从按日期过滤的表中选择数据时遇到问题.
例如:
<块引用>SELECT * FROM MYTABLE WHERE MYTABLE.DATEIN = '23/04/49';
Oracle 错误是:
<块引用>通知错误:错误 SQL: ORA-01843: mes no válido01843. 00000 - 无效月份"*原因:*行动:
可能是表的源数据损坏了,在这种情况下:
- 我该如何解决这个问题?
- 我可以将此日期更改为空吗?
这个select的结果,select * from nls_session_parameters;
,是:
参数值------------------------------ -----------------------------------------NLS_LANGUAGE 西班牙语NLS_TERRITORY 西班牙NLS_CURRENCY ¿NLS_ISO_CURRENCY 西班牙NLS_NUMERIC_CHARACTERS ,.NLS_CALENDAR 格里高利NLS_DATE_FORMAT DD/MM/RRNLS_DATE_LANGUAGE 西班牙语NLS_SORT 西班牙文NLS_TIME_FORMAT HH24:MI:SSXFFNLS_TIMESTAMP_FORMAT DD/MM/RR HH24:MI:SSXFFNLS_TIME_TZ_FORMAT HH24:MI:SSXFF TZRNLS_TIMESTAMP_TZ_FORMAT DD/MM/RR HH24:MI:SSXFF TZRNLS_DUAL_CURRENCY ¿NLS_COMP 二进制NLS_LENGTH_SEMANTICS BYTENLS_NCHAR_CONV_EXCP FALSE
解决方案 您应该使用 to_date
函数 (oracle/functions/to_date.php)
SELECT * FROM MYTABLE WHERE MYTABLE.DATEIN = TO_DATE('23/04/49', 'DD/MM/YY');
I have a problem when try to select data from a table filtering by date.
For example:
SELECT * FROM MYTABLE WHERE MYTABLE.DATEIN = '23/04/49';
The Oracle Error is:
Informe de error: Error SQL: ORA-01843: mes no válido 01843. 00000 - "not a valid month" *Cause: *Action:
Probably the source data of table is corrupted, in this case:
- How can i solve this problem?
- Can I change this dates for null?
The results of this select, select * from nls_session_parameters;
, is:
PARAMETER VALUE
------------------------------ ----------------------------------------
NLS_LANGUAGE SPANISH
NLS_TERRITORY SPAIN
NLS_CURRENCY ¿
NLS_ISO_CURRENCY SPAIN
NLS_NUMERIC_CHARACTERS ,.
NLS_CALENDAR GREGORIAN
NLS_DATE_FORMAT DD/MM/RR
NLS_DATE_LANGUAGE SPANISH
NLS_SORT SPANISH
NLS_TIME_FORMAT HH24:MI:SSXFF
NLS_TIMESTAMP_FORMAT DD/MM/RR HH24:MI:SSXFF
NLS_TIME_TZ_FORMAT HH24:MI:SSXFF TZR
NLS_TIMESTAMP_TZ_FORMAT DD/MM/RR HH24:MI:SSXFF TZR
NLS_DUAL_CURRENCY ¿
NLS_COMP BINARY
NLS_LENGTH_SEMANTICS BYTE
NLS_NCHAR_CONV_EXCP FALSE
解决方案
You should use the to_date
function (oracle/functions/to_date.php
)
SELECT * FROM MYTABLE WHERE MYTABLE.DATEIN = TO_DATE('23/04/49', 'DD/MM/YY');
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