MySQL 选择年和月的第一天
如何在 SELECT 中找到一年的第一天?
How to find first day of year in SELECT?
SELECT `DATE`,`SomeValue1`,`SomeValue2`
FROM `SomeTableName`
WHERE (`DATE` >= [...first day of the year in date format...])
我找到了这个月 - 但我对一年的掌握还不够:(我正在寻找这个用于单独查询以查找月初和现在之间的数据)
I found this for month - but I don't QUITE have the grasp enough for year: (I was looking for this for a separate query to find data between beginning of month and now)
WHERE (`DATE` between DATE_FORMAT(NOW() ,'%Y-%m-01') AND NOW() )
推荐答案
我认为您需要:
WHERE (`DATE` between DATE_FORMAT(NOW() ,'%Y-01-01') AND NOW() )
老实说，你可以这样做:
To be honest, you could do:
WHERE (`DATE` between DATE_FORMAT(NOW() ,'%Y') AND NOW() )
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