可以“list_display"在 Django ModelAdmin 中显示 ForeignKey 字段的属性?

2022-01-25 00:00:00 python django django-models django-admin modeladmin

问题描述

我有一个 Person 模型，它与 Book 有外键关系，它有许多字段，但我最关心的是 author(一个标准的 CharField).

I have a Person model that has a foreign key relationship to Book, which has a number of fields, but I'm most concerned about author (a standard CharField).

话虽如此，在我的 PersonAdmin 模型中，我想使用 list_display 显示 book.author:

With that being said, in my PersonAdmin model, I'd like to display book.author using list_display:

class PersonAdmin(admin.ModelAdmin):
    list_display = ['book.author',]

我已经尝试了所有明显的方法，但似乎没有任何效果.

I've tried all of the obvious methods for doing so, but nothing seems to work.

有什么建议吗?

解决方案

作为另一种选择，您可以进行如下查找:

As another option, you can do look ups like:

class UserAdmin(admin.ModelAdmin):
    list_display = (..., 'get_author')
    
    def get_author(self, obj):
        return obj.book.author
    get_author.short_description = 'Author'
    get_author.admin_order_field = 'book__author'

从 Django 3.2 开始，您可以使用 display() 装饰器:

Since Django 3.2 you can use display() decorator:

class UserAdmin(admin.ModelAdmin):
    list_display = (..., 'get_author')
    
    @display(ordering='book__author', description='Author')
    def get_author(self, obj):
        return obj.book.author

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