如何判断一个日期是否在另外两个日期之间?
问题描述
我有以下代码:
if date in (start, end):
print('in between')
else:
print('No!')
date、start和end都是1/1格式的变量.我应该怎么做才能打印出正确的结果?我尝试将日期设置为 10/2，从 3/14 开始，到 11/7 结束，它打印的是否！"，这意味着它运行不正确.我想必须将它们格式化为日期格式，然后进行比较.
date, start and end are all variables with the format of 1/1. What should I do to have it print out the right result? i tried date as 10/2, start as 3/14 and end as 11/7 and it's print 'No!', which means it's not running right. I guess have to format them to a date format and then compare them.
解决方案
既然你还不满意，我再给你一个答案.不使用日期时间和年份.
As you are still not satisfied, I have another answer for you. Without using datetime and year.
它只是使用内置元组并比较它们:
It just uses built-in tuples and comparing them:
d1 = (3, 28)
d2 = (3, 31)
d3 = (4, 2)
if d1 < d2 < d3:
print("BETWEEN!")
else:
print("NOT!")
您可以轻松地创建这样的元组:
You can create tuple like these easily:
day = 16
month = 4
d = (month, day)
相关文章