在列表中查找最旧/最年轻的日期时间对象

2022-01-25 00:00:00 python datetime compare

问题描述

I've got a list of datetime objects, and I want to find the oldest or youngest one. Some of these dates might be in the future.

from datetime import datetime

datetime_list = [
    datetime(2009, 10, 12, 10, 10),
    datetime(2010, 10, 12, 10, 10),
    datetime(2010, 10, 12, 10, 10),
    datetime(2011, 10, 12, 10, 10), #future
    datetime(2012, 10, 12, 10, 10), #future
]

What's the most optimal way to do so? I was thinking of comparing datetime.now() to each one of those.

解决方案

Oldest:

oldest = min(datetimes)

Youngest before now:

now = datetime.datetime.now(pytz.utc)
youngest = max(dt for dt in datetimes if dt < now)

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