SQL Server 替换，删除特定字符后的所有字符
我的数据看起来像
ID MyText
1 some text; some more text
2 text again; even more text
如何更新 MyText 以删除分号之后的所有内容并包括分号，所以我只剩下以下内容:
How can I update MyText to drop everything after the semi-colon and including the semi colon, so I'm left with the following:
ID MyText
1 some text
2 text again
我查看了 SQL Server Replace，但不能'没有想到检查;"的可行方法
I've looked at SQL Server Replace, but can't think of a viable way of checking for the ";"
推荐答案
使用 LEFT 与 CHARINDEX 结合:
Use LEFT combined with CHARINDEX:
UPDATE MyTable
SET MyText = LEFT(MyText, CHARINDEX(';', MyText) - 1)
WHERE CHARINDEX(';', MyText) > 0
请注意，WHERE 子句会跳过更新没有分号的行.
Note that the WHERE clause skips updating rows in which there is no semicolon.
这里有一些代码来验证上面的 SQL 是否有效:
Here is some code to verify the SQL above works:
declare @MyTable table ([id] int primary key clustered, MyText varchar(100))
insert into @MyTable ([id], MyText)
select 1, 'some text; some more text'
union all select 2, 'text again; even more text'
union all select 3, 'text without a semicolon'
union all select 4, null -- test NULLs
union all select 5, '' -- test empty string
union all select 6, 'test 3 semicolons; second part; third part;'
union all select 7, ';' -- test semicolon by itself
UPDATE @MyTable
SET MyText = LEFT(MyText, CHARINDEX(';', MyText) - 1)
WHERE CHARINDEX(';', MyText) > 0
select * from @MyTable
我得到以下结果:
id MyText
-- -------------------------
1 some text
2 text again
3 text without a semicolon
4 NULL
5 (empty string)
6 test 3 semicolons
7 (empty string)
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