在 Oracle 中将字符串日期转换为日期时间
如何在 oracle 中将此字符串日期转换为日期时间.
How can I convert this string date to datetime in oracle.
2011-07-28T23:54:14Z
使用此代码会引发错误:
Using this code throws an error:
TO_DATE('2011-07-28T23:54:14Z', 'YYYY-MM-DD HH24:MI:SS')
如何做到这一点?
Error report:
SQL Error: ORA-01861: literal does not match format string
01861. 00000 - "literal does not match format string"
*Cause: Literals in the input must be the same length as literals in
the format string (with the exception of leading whitespace). If the
"FX" modifier has been toggled on, the literal must match exactly,
with no extra whitespace.
*Action: Correct the format string to match the literal.
更新:-
TO_DATE('2011-07-28T23:54:14Z', 'YYYY-MM-DD"T"HH24:MI:SS"Z"')
TO_DATE('2011-07-28T23:54:14Z', 'YYYY-MM-DD"T"HH24:MI:SS"Z"')
我只在列中看到日期而不是时间
I only see the date not time in the column
28-JUL-11
推荐答案
试试这个:TO_DATE('2011-07-28T23:54:14Z', 'YYYY-MM-DD"T"HH24:MI:SS"Z"')
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