sql 2005 中的枢轴
我需要旋转一列(数字列).示例需要此数据:
I need to pivot one column (Numbers column). example need this data:
a 1
a 2
b 3
b 4
c 5
d 6
d 7
d 8
d 9
e 10
e 11
e 12
e 13
e 14
看起来像这样
a 1 2
b 3 4
c 5
d 6 7 8 9
e 10 11 12 13 14
任何帮助将不胜感激...
any help would be greatly appreciated...
推荐答案
使用 ROW_NUMBER()
、PIVOT
和一些动态 SQL(但不需要游标):>
Using ROW_NUMBER()
, PIVOT
and some dynamic SQL (but no cursor necessary) :
CREATE TABLE [dbo].[stackoverflow_198716](
[code] [varchar](1) NOT NULL,
[number] [int] NOT NULL
) ON [PRIMARY]
DECLARE @sql AS varchar(max)
DECLARE @pivot_list AS varchar(max) -- Leave NULL for COALESCE technique
DECLARE @select_list AS varchar(max) -- Leave NULL for COALESCE technique
SELECT @pivot_list = COALESCE(@pivot_list + ', ', '') + '[' + CONVERT(varchar, PIVOT_CODE) + ']'
,@select_list = COALESCE(@select_list + ', ', '') + '[' + CONVERT(varchar, PIVOT_CODE) + '] AS [col_' + CONVERT(varchar, PIVOT_CODE) + ']'
FROM (
SELECT DISTINCT PIVOT_CODE
FROM (
SELECT code, number, ROW_NUMBER() OVER (PARTITION BY code ORDER BY number) AS PIVOT_CODE
FROM stackoverflow_198716
) AS rows
) AS PIVOT_CODES
SET @sql = '
;WITH p AS (
SELECT code, number, ROW_NUMBER() OVER (PARTITION BY code ORDER BY number) AS PIVOT_CODE
FROM stackoverflow_198716
)
SELECT code, ' + @select_list + '
FROM p
PIVOT (
MIN(number)
FOR PIVOT_CODE IN (
' + @pivot_list + '
)
) AS pvt
'
PRINT @sql
EXEC (@sql)
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