Python:从间隔映射到值

2022-01-24 00:00:00 python intervals range

问题描述

我正在重构一个函数，给定一系列隐式定义区间的端点，检查区间中是否包含一个数字，然后返回一个对应的(不以任何可计算的方式相关).现在处理这项工作的代码是:

I'm refactoring a function that, given a series of endpoints that implicitly define intervals, checks if a number is included in the interval, and then return a corresponding (not related in any computable way). The code that is now handling the work is:

if p <= 100:
    return 0
elif p > 100 and p <= 300:
    return 1
elif p > 300 and p <= 500:
    return 2
elif p > 500 and p <= 800:
    return 3
elif p > 800 and p <= 1000:
    return 4
elif p > 1000:
    return 5

这在 IMO 中非常可怕，并且缺少间隔和返回值都是硬编码的.当然可以使用任何数据结构.

Which is IMO quite horrible, and lacks in that both the intervals and the return values are hardcoded. Any use of any data structure is of course possible.

解决方案

import bisect
bisect.bisect_left([100,300,500,800,1000], p)

这里是文档:bisect

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