Python - 不支持的类型:范围和范围
问题描述
我在尝试运行脚本时遇到了这个奇怪的错误,代码似乎是正确的,但似乎 python (3) 不喜欢这部分:
I'm getting this strange error trying to run a script, the code appears to be correct but it seems python (3) didn't liked this part:
def function(x):
if integer:
return int(x)
else:
return x
non_nil = randrange(21)
d = dict([(randrange(101), Racional(coeff(randrange(-20,20)),
coeff(choice(range(-30,0)+
range(1,30)))))
for k in range(non_nil)])
我收到以下错误:
for k in range(non_nil)]) unsupported operand type(s) for +: 'range' and 'range'
我已经尝试将最后四行放在一个单独的行中,但 python 返回相同的错误.
I already tried to put the last four lines in a single one but python returns the same error.
解决方案
这是因为 Python 3 range
不像 Python 2 那样返回 list
.这段代码是为 Python 2 编写.
This is because Python 3 range
does not return a list
, unlike Python 2. This code was written for Python 2.
此代码应该更改:
range(-30,0) + range(1,30)
应该改为:
[*range(-30,0), *range(1,30)]
在 Python 3.5 之前(2015 年,PEP 448 - 附加解包概括),你不能在列表中使用 *
,必须这样写(或者你可能更喜欢这样):
Prior to Python 3.5 (2015, PEP 448 - Additional Unpacking Generalizations), you cannot use *
inside lists, and must write it this way instead (or you may prefer this):
list(range(-30,0)) + list(range(1,30))
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