如何将正负十进制数列表标准化为特定范围
问题描述
我有一个十进制数列表如下:
I have a list of decimal numbers as follows:
[-23.5, -12.7, -20.6, -11.3, -9.2, -4.5, 2, 8, 11, 15, 17, 21]
我需要规范化这个列表以适应 [-5,5] 范围.
我如何在python中做到这一点?
I need to normalize this list to fit into the range [-5,5].
How can I do it in python?
解决方案
获取输入范围很简单:
old_min = min(input)
old_range = max(input) - old_min
这是棘手的部分.您可以乘以新范围并除以旧范围，但这几乎可以保证顶部存储桶只会得到一个值.您需要扩大输出范围，使顶部存储桶与所有其他存储桶的大小相同.
Here's the tricky part. You can multiply by the new range and divide by the old range, but that almost guarantees that the top bucket will only get one value in it. You need to expand your output range so that the top bucket is the same size as all the other buckets.
new_min = -5
new_range = 5 + 0.9999999999 - new_min
output = [floor((n - old_min) / old_range * new_range + new_min) for n in input]
相关文章