mysql中每组的行数

2021-11-20 00:00:00 mysql

我想根据这个场景生成查询结果，可以根据crew_id和type创建行号.

I want to produce query result base on this scenario that can create row number according to crew_id and type.

id   crew_id   amount    type
 1      4       1000      AUB
 2      4       1500      AUB
 3      5       8000      CA
 4      4       1000      CA
 5      5       1000      AUB
 6      6       3000      AUB
 7      4       2000      CA
 8      6       3500      AUB
 9      4       5000      AUB
 10     5       9000      CA
 11     5       1000      CA

OUTPUT 必须是 ff:

OUTPUT must be the ff:

id    crew_id   amount   type    row_number
 1      4       1000      AUB        1    
 2      4       1500      AUB        2 
 9      4       5000      AUB        3
 4      4       1000      CA         1
 7      4       2000      CA         2
 5      5       1000      AUB        1
 3      5       8000      CA         1
 10     5       9000      CA         2
 11     5       1000      CA         3
 6      6       3000      AUB        1
 6      6       3000      AUB        2

我只想要这个输出中的单个 select 语句

I want a single select statement only in this output

推荐答案

这个问题很老了.但我想发布它以防有人遇到同样的问题.

The question is quite old. But I would like to post it in case someone will have a same problem.

首先，描述的答案不正确.例如，对于

First of all, described answers do not work correct. For example, for 

id   crew_id   amount    type
1      4       1000      AUB
2      4       1500      AUB
5      5       1000      AUB
6      6       3000      AUB
8      6       3500      AUB
9      4       5000      AUB

(我刚刚删除了类型为CA"的行)结果表将是

(I just removed rows with type 'CA') the result table will be 

id   crew_id   amount    rank   type
1      4       1000      1      AUB
2      4       1500      2      AUB
9      4       5000      3      AUB
5      5       1000      4      AUB
6      6       3000      5      AUB
8      6       3500      6      AUB

所以实际上它并没有同时使用crew_id 和type，它只是使用了type.

So in fact it doesn't use both crew_id and type, it just uses type.

这是我解决这个问题的方法(可能有一种比使用两个嵌套的CASE"更优雅的方法，但你明白了):

Here is how I solved this problem (probably there is a more elegant way to do it than use two nested 'CASE's, but you get the idea):

SELECT id,
    amount,
    CASE crew_id 
        WHEN @curCrewId THEN
            CASE type 
                WHEN @curType THEN @curRow := @curRow + 1 
                ELSE @curRow := 1
            END
        ELSE @curRow :=1
    END AS rank,
    @curCrewId := crew_id AS crew_id,
    @curType := type AS type
FROM Table1 p
JOIN (SELECT @curRow := 0, @curCrewId := 0, @curType := '') r
ORDER BY crew_id, type

主要思想仍然存在.我刚刚添加了一个变量@curCrewId.如果有人需要使用 3 个变量进行分组，那么只需使用 3 个变量和 3 个嵌套的CASE".:)

The main idea remain. I just added a variable @curCrewId. If someone need to use 3 variables for grouping, so just use 3 variables and 3 nested 'CASE's. :)

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