在 Python 中一次遍历 2 个列表

2022-01-24 00:00:00 python list iteration

问题描述

我想向两个 Python 列表的成员共享/分配特定数量.list1 的成员各有双份，list2 的成员各有一份，然后打印出结果，并分配名称和值.以下是我的示例代码:

I want to share/divide a specific amount to the members of two Python lists. The members of list1 will have double share each, while the members of list2 will have single share each, then print out the result, with name and value allocated. The following is my sample code:

reminder = float(85000)

list1 = ['Designer', 'Coder', 'Supervisor']
list2 = ['Artist', 'Attendant', 'Usher]

for i,j in list1 and list2:
    print(i, (reminder/9)*2)
    print(j, (reminder/9)*1)

当我运行上面的代码时，我得到了一个异常:

When I ran the above code I got an exception:

Traceback (most recent call last):
  File "C:Python33eminder.py", line 6, in <module>
    for i,j in list1 and list2:
ValueError: too many values to unpack (expected 2)

我搜索了有关同一主题的先前帖子，但找不到解决方案.

I searched previous posts on same topic but could't come across a solution.

请问我该怎么做?

解决方案

你应该使用 zip() 内置函数.

You should use zip() built-in function.

for i, j in zip(list1, list2):
    print(i, (reminder/9)*2)
    print(j, (reminder/9)*1)

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