Pythonic迭代列表中的滑动窗口对?
问题描述
在滑动对中迭代列表的最 Pythonic 最有效的方法是什么?这是一个相关的例子:
What's the most Pythonic efficient way to iterate over a list in sliding pairs? Here's a related example:
>>> l
['a', 'b', 'c', 'd', 'e', 'f', 'g']
>>> for x, y in itertools.izip(l, l[1::2]): print x, y
...
a b
b d
c f
这是成对的迭代，但是我们如何才能在滑动对上进行迭代呢?含义迭代对:
this is iteration in pairs, but how can we get iteration over a sliding pair? Meaning iteration over the pairs:
a b
b c
c d
d e
etc.
这是对对的迭代，除了每次将对滑动 1 个元素而不是 2 个元素.谢谢.
which is iteration over the pairs, except sliding the pair by 1 element each time rather than by 2 elements. thanks.
解决方案
怎么样:
for x, y in itertools.izip(l, l[1:]): print x, y
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