使用 SQL 查询查找最近的纬度/经度
我有纬度和经度,我想从数据库中提取记录,该记录具有距离最近的纬度和经度,如果该距离超过指定的距离,则不要检索它.
I have latitude and longitude and I want to pull the record from the database, which has nearest latitude and longitude by the distance, if that distance gets longer than specified one, then don't retrieve it.
表结构:
id
latitude
longitude
place name
city
country
state
zip
sealevel
推荐答案
SELECT latitude, longitude, SQRT(
POW(69.1 * (latitude - [startlat]), 2) +
POW(69.1 * ([startlng] - longitude) * COS(latitude / 57.3), 2)) AS distance
FROM TableName HAVING distance < 25 ORDER BY distance;
其中 [starlat] 和 [startlng] 是开始测量距离的位置.
where [starlat] and [startlng] is the position where to start measuring the distance.
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