是否可以将列表转换为嵌套的键字典*无需*递归?
问题描述
假设我有一个如下列表:
Supposing I had a list as follows:
mylist = ['a','b','c','d']
是否可以从这个列表中不使用使用递归/递归函数创建以下字典?
Is it possible to create, from this list, the following dict without using recursion/a recursive function?
{
'a': {
'b': {
'c': {
'd': { }
}
}
}
}
解决方案
对于简单的情况,简单的迭代和构建,从头到尾都可以:
For the simple case, simply iterate and build, either from the end or the start:
result = {}
for name in reversed(mylist):
result = {name: result}
或
result = current = {}
for name in mylist:
current[name] = {}
current = current[name]
第一个解决方案也可以使用 reduce()代码>:
The first solution can also be expressed as a one-liner using reduce()
:
reduce(lambda res, name: {name: res}, reversed(mylist), {})
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