以递归方式将 xml 粉碎到数据库中
我有以下 XML 数据和元素表.
I have the following XML data and the Element table.
DECLARE @input XML = '<root>
<C1>
<C2>
<C3> <C4>data1</C4> </C3>
</C2>
<C2>
<C3>data2</C3>
</C2>
</C1>
<D1>
<D2>data3</D2>
<D2>data4</D2>
</D1>
</root>'
元素表:(这只是一个例子,因此可以更改以匹配适当的解决方案.)
Element table:( this is just an example so can be changed to match an appropriate solution.)
CREATE TABLE Element ( elementId INT IDENTITY PRIMARY KEY,
elementName VARCHAR (200) NOT NULL,
parentId INT,
data VARCHAR(300) );
根据@input,根元素是C1和D1的父元素,那么C1是C2的父元素,...
According to @input the root element is parent of C1 and D1, then C1 is C2 parent, ...
SQL server 2012/2014 使用 CTE(或任何其他类型的 SQL 对象)编写存储过程以递归方式将所有元素名称放入 Element 表的解决方案是什么?
What is the solution for SQL server 2012/2014 to code a stored procedure with CTE (or any other type of SQL object) to recursively put all element names into the Element table?
在这种情况下,数据列填充了数据,C4 和第二个 C3 和 D2 元素有数据,其余元素为空.
data column fills with data in this case, the C4 and the second C3, and D2 elements have data the rest of element are null.
我也看到了分层数据类型,我想知道这是否有助于解决这个问题?
I also saw Hierarchical Data type and I wonder if that could be helpful to solve this problem?
推荐答案
With OpenXML 您可以使用 元属性.
With OpenXML you can get a table representation of your XML with ID
and ParentID
columns using the metaproperties.
在合并中使用 XML 查询将允许您创建映射表elementId
标识列和来自 XML 的 DOM 节点 ID 之间.
Using the XML query in a merge will allow you to create a mapping table between the elementId
identity column and the DOM node id from the XML.
最后一步是使用映射表更新Element
中的parentId
.
The last step is to use the mapping table to update parentId
in Element
.
SQL 小提琴
MS SQL Server 2008 架构设置:
CREATE TABLE Element ( elementId INT IDENTITY PRIMARY KEY,
elementName VARCHAR (200) NOT NULL,
parentId INT,
data VARCHAR(300) );
查询 1:
declare @input xml = '
<root>
<C1>
<C2>
<C3>
<C4>data1</C4>
</C3>
</C2>
<C2>
<C3>data2</C3>
</C2>
</C1>
<D1>
<D2>data3</D2>
<D2>data4</D2>
</D1>
</root>';
-- OpenXML handle
declare @D int;
-- Table that capture output of merge with mapping between
-- DOM node id and the identity column elementID in Element
declare @T table
(
ID int,
ParentID int,
ElementID int
);
-- Parse XML and get a handle
exec sp_xml_preparedocument @D output, @input;
-- Add rows to Element and fill the mapping table @T
merge into dbo.Element as E
using (
select *
from openxml(@D, '//*') with
(
ID int '@mp:id',
ParentID int '@mp:parentid',
Data varchar(300) 'text()',
ElementName varchar(200) '@mp:localname'
)
) as S
on 0 = 1
when not matched by target then
insert (elementName, data) values (S.ElementName, S.data)
output S.ID, S.ParentID, inserted.elementID into @T;
-- Update parentId in Elemet
update E
set parentId = T2.ElementID
from dbo.Element as E
inner join @T as T1
on E.elementId = T1.ElementID
inner join @T as T2
on T1.ParentID = T2.ID
-- Relase the XML document
exec sp_xml_removedocument @D;
select *
from Element;
结果:
| ELEMENTID | ELEMENTNAME | PARENTID | DATA |
|-----------|-------------|----------|--------|
| 1 | root | (null) | (null) |
| 2 | C1 | 1 | (null) |
| 3 | C2 | 2 | (null) |
| 4 | C3 | 3 | (null) |
| 5 | C4 | 4 | data1 |
| 6 | C2 | 2 | (null) |
| 7 | C3 | 6 | data2 |
| 8 | D1 | 1 | (null) |
| 9 | D2 | 8 | data3 |
| 10 | D2 | 8 | data4 |
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