使用 Python 解析 Gmail 并将所有早于日期的内容标记为“已读"
问题描述
长话短说，我创建了一个新的 gmail 帐户，并将其他几个帐户关联到该帐户(每个帐户都有 1000 条消息)，我正在导入这些帐户.所有导入的邮件都以未读的形式到达，但我需要它们显示为已读.
Long story short, I created a new gmail account, and linked several other accounts to it (each with 1000s of messages), which I am importing. All imported messages arrive as unread, but I need them to appear as read.
我对python有一点经验，但是我只使用过mail和imaplib模块来发送邮件，没有处理账户.
I have a little experience with python, but I've only used mail and imaplib modules for sending mail, not processing accounts.
有没有办法批量处理收件箱中的所有项目，并将早于指定日期的邮件标记为已读?
Is there a way to bulk process all items in an inbox, and simply mark messages older than a specified date as read?
解决方案
typ, data = M.search(None, '(BEFORE 01-Jan-2009)')
for num in data[0].split():
M.store(num, '+FLAGS', '\Seen')
这是对 imaplib 文档页面中的代码的轻微修改存储方法.我从 RFC 3501 中找到了要使用的搜索条件.这应该可以帮助您入门.
This is a slight modification of the code in the imaplib doc page for the store method. I found the search criteria to use from RFC 3501. This should get you started.
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