如何在 SQL Server 的 INSERT 存储过程中生成唯一的增量员工代码(模式:E0001, E0002, E0003, ... )?
我想在 INSERT 存储过程中插入单个记录时生成唯一的员工代码.
I want to generate unique employee code at a time of inserting a single record in INSERT stored procedure.
第一次程序调用将生成员工代码为 E0001,第二次调用将生成 E0002,...
First-time procedure call will generate employee code as E0001, the second call will generate E0002, ...
预期的输出应该是这样的,
The expected output should look like,
EmployeeCode EmployeeName
-------------------------------
E0001 A
E0002 B
E0003 C
E0004 D
E0005 E
' '
' '
' '
E9999 ZZZ
推荐答案
您可以在默认情况下将序列值嵌入到自定义格式的字符串中,并使用检查约束强制执行它.像这样:
You can embed a sequence value into a custom-formatted string in a default, and enforce it with a check constraint. Like this:
--drop table if exists Employee
--drop sequence seq_Employee
--go
create sequence seq_Employee
start with 1
increment by 1
go
CREATE TABLE Employee
(
EmployeeCode char(5) PRIMARY KEY
default 'E' + format((next value for seq_Employee),'0000' )
check (EmployeeCode like 'E[0-9][0-9][0-9][0-9]'),
EmployeeName VARCHAR(50) NOT NULL
)
go
insert into Employee(EmployeeName)
values ('A'),('B'),('C'),('D'),('E')
select *
from Employee
输出
EmployeeCode EmployeeName
------------ --------------------------------------------------
E0001 A
E0002 B
E0003 C
E0004 D
E0005 E
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