在第 13 行动态和第 12 行静态值之后使用公式

2021-09-10 00:00:00 sql sql-server-2005 tsql sql-server-2008 sql-server

下面是我用来创建视图的 SQL 查询

Below is the SQL Query I used to create as view

CREATE VIEW [v_AMP_C] AS SELECT dbo.IC_Raw_In.I_Date, dbo.IC_Raw_In.I_O_P, dbo.IC_Raw_In.I_O_H, dbo.IC_Raw_In.I_O_L, dbo.IC_Raw_In.I_C_O, dbo.AMPS12_C.AMPS12_C FROM dbo.IC_Raw_In INNER JOIN dbo.AMPS12_C ON dbo.IC_Raw_In.I_Serial = dbo.AMPS12_C.i_serial

使用批量插入dbo.IC_Raw_In将数据导入该表，数据类型为Money，I_Date除外.

and the data is imported to this table by useing a bulk insert dbo.IC_Raw_In and data type are Money except I_Date.

然后当我运行查询时，即.

Then when i ran the query i.e,.

select * from v_AMP_C i 得到以下作为输出

I_Date I_O_P I_O_H I_O_L I_C_O AMPS12_C 01/10/11 509.75 515 508 512.45 512.45 01/10/11 511.7 511.7 506.1499 506.5499 509.4999 01/10/11 507.1499 510.25 507.1499 510.25 509.7499 01/10/11 510 512.3499 509.2999 512.3499 510.3999 01/10/11 512.5 512.5 511.1499 512 510.7199 01/10/11 512.25 512.5 510.1 510.95 510.7583 01/10/11 510.5499 511.7999 510 511.7999 510.9071 01/10/11 511.1 511.85 508.1499 508.8999 510.6562 01/10/11 508.8999 510 508.5 509.95 510.5777 01/10/11 509.8999 509.8999 508.5 508.85 510.4049 01/10/11 509.5 511.2 509 510.5 510.4136 01/10/11 510.5 511.7999 510.1 510.2 [b]510.3958[/b] 01/10/11 510.2999 511.35 510.25 510.75 510.2541 01/10/11 510.35 512 510.35 510.95 510.6208 01/10/11 510.95 511.7999 510.6 511.1 510.6916 01/10/11 511.0499 511.35 509.1 509.1 510.4208 01/10/11 509.5 509.5 508.1 508.5 510.1291 01/10/11 508.45 508.95 507 507 509.7999 01/10/11 507 508.2 503.2999 503.2999 509.0916 01/10/11 504 505 503.5 504.6499 508.7374 01/10/11 505.45 506.35 504 504.7 508.2999 01/10/11 504.7 505.5 504.2 505.5 508.0208 01/10/11 505.35 505.7 503.1 503.6499 507.4499 01/10/11 504.5 504.5 499.5499 500.5 506.6416 01/10/11 500.45 502 500.25 501 505.8291 01/10/11 501 501.2999 499.5499 500.3999 504.9499 01/10/11 500.45 500.7999 498.6499 498.6499 503.9124 01/10/11 498.7 499.25 498.0499 498.35 503.0166 01/10/11 498.75 499.95 498.7 499 502.2249 01/10/11 499.25 499.6499 498.6499 499.45 501.5957 01/10/11 499.2999 501.1499 499.1 500.8999 501.3957 01/10/11 501.1 502.5 500.5499 502.5 501.2166 01/10/11 502.35 502.95 501 501.5 500.9499 01/10/11 501.5 501.5 500 500.5 500.5333 01/10/11 500 501.35 499.5 499.7999 500.2124 01/10/11 499.95 500.3999 499.2999 500.2999 500.1957 01/10/11 500 501.3999 499.5 499.6499 500.0832 01/10/11 499.7999 501.25 499.6499 500.0499 500.0541

现在我想编写一个 SQL 查询，以在名为 C12WR 的新列中获取结果以解决以下问题.

Now I want write a SQL Query to get results in new Column called C12WR for the below question.

我想排除(使用 NULL)C12WR 列的前 11 行，并在 C12WR 列的第 12 行使用AMPS12_C"中的静态值(在上表结果中，值为510.3958"标记为粗体.每次我将数据导入我的表时，该值都会发生变化，因此每次都会动态变化.并且在 AMPS12_C 列中，它应该在第 13 行到表末尾之后计算以下公式.

I want to exclude(Use NULL) the first 11 rows in C12WR Column, and in 12th row of C12WR Column "use a static value which is in "AMPS12_C" (In the above shown table results the value is "510.3958" marked as bold). This value will change every time i import the data to my table so the will change dynamically every time. And in the AMPS12_C Column it should calculate the below formula after 13th row to end of the table.

After 13th Row in C12WR Column = (the value of above row (that is currunt row number -1) from C12WR *11 + Current row value from I_C_O Column) /12

所以如果我计算它应该代表上面的公式如下..(我不想使用任何静态值......对于这个公式的例子，我在这里采用静态值只是为了结果容易解释)

so if i calculate it should represent above formulas as below..(I don't want to use any static values...for the example of this formula I am taking a static values here just for the results to easy of explanation)

=(510.3958*11+510.2)/12

在运行所需的查询后，我应该得到类似于下面的输出

and after run the desired query i should get the output similar to below

I_Date I_O_P I_O_H I_O_L I_C_O AMPS12_C C12WR 01/10/11 509.75 515 508 512.4500122 512.45 NULL 01/10/11 511.7000122 511.7000122 506.1499939 506.5499878 509.4999 NULL 01/10/11 507.1499939 510.25 507.1499939 510.25 509.7499 NULL 01/10/11 510 512.3499756 509.2999878 512.3499756 510.3999 NULL 01/10/11 512.5 512.5 511.1499939 512 510.7199 NULL 01/10/11 512.25 512.5 510.1000061 510.9500122 510.7583 NULL 01/10/11 510.5499878 511.7999878 510 511.7999878 510.9071 NULL 01/10/11 511.1000061 511.8500061 508.1499939 508.8999939 510.6562 NULL 01/10/11 508.8999939 510 508.5 509.9500122 510.5777 NULL 01/10/11 509.8999939 509.8999939 508.5 508.8500061 510.4049 NULL 01/10/11 509.5 511.2000122 509 510.5 510.4136 NULL 01/10/11 510.5 511.7999878 510.1000061 510.2000122 510.3958333 510.3958333 01/10/11 510.2999878 511.3500061 510.25 510.75 510.2541657 510.3795149 01/10/11 510.3500061 512 510.3500061 510.9500122 510.6208344 510.4103887 01/10/11 510.9500122 511.7999878 510.6000061 511.1000061 510.6916682 510.4553573 01/10/11 511.0499878 511.3500061 509.1000061 509.1000061 510.4208374 510.509078 01/10/11 509.5 509.5 508.1000061 508.5 510.1291707 510.3916554 01/10/11 508.4500122 508.9500122 507 507 509.8000031 510.2340174 01/10/11 507 508.2000122 503.2999878 503.2999878 509.0916697 509.964516 01/10/11 504 505 503.5 504.6499939 508.7375031 509.4091386 01/10/11 505.4500122 506.3500061 504 504.7000122 508.3000031 509.0125432 01/10/11 504.7000122 505.5 504.2000122 505.5 508.0208359 508.6531656 01/10/11 505.3500061 505.7000122 503.1000061 503.6499939 507.450002 508.3904018 01/10/11 504.5 504.5 499.5499878 500.5 506.6416677 507.9953678 01/10/11 500.4500122 502 500.25 501 505.8291677 507.3707539 01/10/11 501 501.2999878 499.5499878 500.3999939 504.9499995 506.8398577 01/10/11 500.4500122 500.7999878 498.6499939 498.6499939 503.9124985 506.3032024 01/10/11 498.7000122 499.25 498.0499878 498.3500061 503.0166651 505.665435 01/10/11 498.75 499.9500122 498.7000122 499 502.2249985 505.0558159 01/10/11 499.25 499.6499939 498.6499939 499.4500122 501.5958328 504.5511646 01/10/11 499.2999878 501.1499939 499.1000061 500.8999939 501.3958333 504.1260686 01/10/11 501.1000061 502.5 500.5499878 502.5 501.2166672 503.857229 01/10/11 502.3500061 502.9500122 501 501.5 500.9499995 503.7441266 01/10/11 501.5 501.5 500 500.5 500.5333328 503.557116 01/10/11 500 501.3500061 499.5 499.7999878 500.212499 503.3023564 01/10/11 499.9500122 500.3999939 499.2999878 500.2999878 500.1958313 503.0104923 01/10/11 500 501.3999939 499.5 499.6499939 500.0833308 502.784617 01/10/11 499.7999878 501.25 499.6499939 500.0499878 500.0541636 502.5233984

寻求帮助写上面的SQL Query

looking for help to write above SQL Query

推荐答案

这个概念有一定的错误" - 主要是因为 X 行和 Y 行之间的任何此类行相互关系都依赖于按指定顺序排列的行- 我没有看到现在.IT 与 SQL 语言的基于集合的方面背道而驰.

There is a certain 'wrongness' with the concept - primarily because any such row inter-relation between row X and Y relies on the rows being in a specified order - which I do not see present. IT goes against the set-based aspects of the SQL language in effect.

就 SQL 而言 - 缓慢/昂贵的方法是将表连接到自身，但您必须能够使用排名函数创建行号确定性才能使其工作.

In terms of SQL - the slow / expensive way to do it is to join the table to itself, but you have to be able to create row numbers deterministicallt using a ranking function for this to work.

标准 T-SQL 没有 Lag/Lead 能力(引用上一行/下一行的能力.) - 它确实存在于 MDX 语言中，但这使这进一步复杂化.

Standard T-SQL does not have a Lag / Lead ability (the abilty to reference the previous / nextrow.) - It does exist in the MDX langauge but that complicates this further.

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