“timestampadd"不是可识别的内置函数名称
我正在尝试将 6 位日期转换为常规日期.
I'm trying to convert a 6 digit date into a regular looking date.
目前我们在数据库中有这个:
Currently we have this in the DB:
734562
734776
734837
这是我正在尝试的:
select
timestampadd(
sql_tsi_day
,rbaging.billing_period_end
,cast('0001-01-01' as sql_timestamp)
)
-1,*
from
[kslap208].[c021]..RB_Resident_Aging rbaging
我得到的错误是:
Msg 195, Level 15, State 10, Line 5
'timestampadd' is not a recognized built-in function name.
如何将此字段转换为常规日期字段?
how do i convert this field into a regular date field?
推荐答案
如果远程源是一个整数,或者可以强制转换为一个,我相信应该这样做:
If the remote source is an integer, or can be cast to one, I believe this should do it:
SELECT DATEADD(DD, Field - 730000, '2001-01-01')
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