TSQL 返回存在的内容
这是此问题的后续问题TSQL 搜索文本
我的情况如下
declare @vendor as table (vName varchar(max))
insert into @vendor
select *
from
(
values
('Maccro'),
('Accro')
) t (one)
declare @transaction as table (descr varchar(max))
insert into @transaction
select *
from
(
values
('recl Maccro something'),
('lrec Accro Maccro'),
('lrec Maccr0'),
('Maccro indeed'),
('ACCR Accro'),
('Raac else')
) t (one)
我可以运行以下查询
Select
a.descr,
CASE WHEN EXISTS(select * From @vendor b
where Charindex(b.Vname, a.descr) > 0)
then 1 else 0 End [doesContain]
from @transaction a
返回以下内容
| descr | doesContain |
| --------------------- | ----------- |
| recl Maccro something | 1 |
| lrec Accro Maccro | 1 |
| lrec Maccr0 | 0 |
| Maccro indeed | 1 |
| ACCR Accro | 1 |
| Raac else | 0 |
但是是否有可能看到 doesContain
返回 1 的值,即 @vendor
表中的值,Exists
返回一场比赛.
But is it possible to see on what value it returns 1 for doesContain
, i.e. on what value from @vendor
table, Exists
returns a match.
我想要的输出如下
| descr | doesContain | containsWhat |
| --------------------- | ----------- | ------------ |
| recl Maccro something | 1 | Maccro |
| lrec Accro Maccro | 1 | Accro |
| lrec Maccr0 | 0 | |
| Maccro indeed | 1 | Maccro |
| ACCR Accro | 1 | Accro |
| Raac else | 0 | |
推荐答案
使用 @transaction
的 LEFT
连接到 @vendor
和 FIRST_VALUE()
获取第一次出现的窗口函数:
Use a LEFT
join of @transaction
to @vendor
and FIRST_VALUE()
window function to get the 1st occurrence:
Select distinct
a.descr,
CASE WHEN b.Vname is not null then 1 else 0 End [doesContain],
first_value(b.Vname) over (partition by a.descr order by Charindex(b.Vname, a.descr)) containsWhat
from @transaction a left join @vendor b
on Charindex(b.Vname, a.descr) > 0
请参阅演示.
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