删除表中的多个重复行
我在一个表中有多组重复项(一个表有 3 条记录,另一个表有 2 条记录,等等)- 存在多于 1 条记录的多行.
I have multiple groups of duplicates in one table (3 records for one, 2 for another, etc) - multiple rows where more than 1 exists.
以下是我想删除它们的方法,但是无论有多少重复项,我都必须运行脚本:
Below is what I came up with to delete them, but I have to run the script for however many duplicates there are:
set rowcount 1
delete from Table
where code in (
select code from Table
group by code
having (count(code) > 1)
)
set rowcount 0
这在一定程度上效果很好.我需要为每组重复项运行它,然后它只删除 1 个(这是我现在需要的全部).
This works well to a degree. I need to run this for every group of duplicates, and then it only deletes 1 (which is all I need right now).
推荐答案
如果您在表中有一个键列,那么您可以使用它来唯一标识表中的不同"行.
If you have a key column on the table, then you can use this to uniquely identify the "distinct" rows in your table.
只需使用子查询来识别唯一行的 ID 列表,然后删除该集合之外的所有内容.类似......的东西
Just use a sub query to identify a list of ID's for unique rows and then delete everything outside of this set. Something along the lines of.....
create table #TempTable
(
ID int identity(1,1) not null primary key,
SomeData varchar(100) not null
)
insert into #TempTable(SomeData) values('someData1')
insert into #TempTable(SomeData) values('someData1')
insert into #TempTable(SomeData) values('someData2')
insert into #TempTable(SomeData) values('someData2')
insert into #TempTable(SomeData) values('someData2')
insert into #TempTable(SomeData) values('someData3')
insert into #TempTable(SomeData) values('someData4')
select * from #TempTable
--Records to be deleted
SELECT ID
FROM #TempTable
WHERE ID NOT IN
(
select MAX(ID)
from #TempTable
group by SomeData
)
--Delete them
DELETE
FROM #TempTable
WHERE ID NOT IN
(
select MAX(ID)
from #TempTable
group by SomeData
)
--Final Result Set
select * from #TempTable
drop table #TempTable;
或者,您可以使用 CTE,例如:
Alternatively you could use a CTE for example:
WITH UniqueRecords AS
(
select MAX(ID) AS ID
from #TempTable
group by SomeData
)
DELETE A
FROM #TempTable A
LEFT outer join UniqueRecords B on
A.ID = B.ID
WHERE B.ID IS NULL
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