带有损坏的子选择的查询应该导致错误但返回行

I don't understand the behaviour in this case. In my understanding a query with an invalid sub-query should result in an error. But in this example it returns some rows.

测试数据:

create table test_values ( tst_id number, tst_id2 number, tst_value varchar2( 10 ) );

create table test_lookup ( tst_id number, tst_value varchar2( 10 ) );

insert into test_values( tst_id, tst_id2, tst_value ) values ( 1, 2, 'a' );
insert into test_values( tst_id, tst_id2, tst_value ) values ( 1, 2, 'b' );
insert into test_values( tst_id, tst_id2, tst_value ) values ( 2, 2,'c' );
insert into test_values( tst_id, tst_id2, tst_value ) values ( 2, 2,'d' );

insert into test_lookup( tst_id, tst_value ) values ( 1, 'findMe' );

commit;

按预期工作:

select * from test_values where tst_id in ( select tst_id from test_lookup where tst_value = 'findMe' );

/*
    TST_ID    TST_ID2 TST_VALUE 
---------- ---------- ----------
         1          2 b         
         1          2 a   
*/

select tst_id2 from test_lookup where tst_value = 'findMe'; 
--ORA-00904: "TST_ID2": invalid identifier

但以下查询也在检索行，显然是通过从test_values"表中获取test_id2"列，而不是从子查询中所述的test_lookup"表中获取，尽管没有使用别名内部和外部.

select * from test_values where tst_id in ( select tst_id2 from test_lookup where tst_value = 'findMe' );

/*
   TST_ID    TST_ID2 TST_VALUE  
---------- ---------- ----------
         2          2 c         
         2          2 d         
*/

select *
from   test_values tv
where  tv.tst_id in (select tv.tst_id2
                     from   test_lookup tl
                     where  tl.tst_value = 'findMe');