在 SQL Server 中使用“透视"将行转换为列

2022-01-22 00:00:00 pivot pivot-table sql sql-server

我已经阅读了 MS 数据透视表上的内容，但我仍然无法正确解决这个问题.

I have read the stuff on MS pivot tables and I am still having problems getting this correct.

我有一个正在创建的临时表，我们会说第 1 列是商店编号，第 2 列是周数，最后第 3 列是某种类型的总数.周数也是动态的，商店数是静态的.

I have a temp table that is being created, we will say that column 1 is a Store number, and column 2 is a week number and lastly column 3 is a total of some type. Also the Week numbers are dynamic, the store numbers are static.

Store      Week     xCount
-------    ----     ------
102        1        96
101        1        138
105        1        37
109        1        59
101        2        282
102        2        212
105        2        78
109        2        97
105        3        60
102        3        123
101        3        220
109        3        87

我希望它以数据透视表的形式出现，如下所示:

I would like it to come out as a pivot table, like this:

Store        1          2          3        4        5        6....
----- 
101        138        282        220
102         96        212        123
105         37        
109

将数字存储在侧面，周数存储在顶部.

Store numbers down the side and weeks across the top.

推荐答案

如果您使用的是 SQL Server 2005+，那么您可以使用 PIVOT 函数将数据从行转换为列.

If you are using SQL Server 2005+, then you can use the PIVOT function to transform the data from rows into columns.

听起来如果周数未知，您将需要使用动态 sql，但最初使用硬编码版本更容易看到正确的代码.

It sounds like you will need to use dynamic sql if the weeks are unknown but it is easier to see the correct code using a hard-coded version initially.

首先，这里有一些快速的表定义和数据供使用:

First up, here are some quick table definitions and data for use:

CREATE TABLE yt 
(
  [Store] int, 
  [Week] int, 
  [xCount] int
);
    
INSERT INTO yt
(
  [Store], 
  [Week], [xCount]
)
VALUES
    (102, 1, 96),
    (101, 1, 138),
    (105, 1, 37),
    (109, 1, 59),
    (101, 2, 282),
    (102, 2, 212),
    (105, 2, 78),
    (109, 2, 97),
    (105, 3, 60),
    (102, 3, 123),
    (101, 3, 220),
    (109, 3, 87);

如果您的值是已知的，那么您将对查询进行硬编码:

If your values are known, then you will hard-code the query:

select *
from 
(
  select store, week, xCount
  from yt 
) src
pivot
(
  sum(xcount)
  for week in ([1], [2], [3])
) piv;

参见 SQL 演示

那么如果您需要动态生成周数，您的代码将是:

Then if you need to generate the week number dynamically, your code will be:

DECLARE @cols AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX)

select @cols = STUFF((SELECT ',' + QUOTENAME(Week) 
                    from yt
                    group by Week
                    order by Week
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

set @query = 'SELECT store,' + @cols + ' from 
             (
                select store, week, xCount
                from yt
            ) x
            pivot 
            (
                sum(xCount)
                for week in (' + @cols + ')
            ) p '

execute(@query);

请参阅 SQL 演示.

动态版本，生成应转换为列的 week 数字列表.两者都给出相同的结果:

The dynamic version, generates the list of week numbers that should be converted to columns. Both give the same result:

| STORE |   1 |   2 |   3 |
---------------------------
|   101 | 138 | 282 | 220 |
|   102 |  96 | 212 | 123 |
|   105 |  37 |  78 |  60 |
|   109 |  59 |  97 |  87 |

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