Plotly:如何手动设置 plotly express 散点图中点的颜色?

2022-01-21 00:00:00 python plotly plotly-python

问题描述

https://plotly.com/python/line-and-scatter/ 有许多散点图示例,但没有一个向您展示如何在 px.scatter 中设置所有点的颜色:

https://plotly.com/python/line-and-scatter/ has many scatter plot examples, but not a single one showing you how to set all the points' colours within px.scatter:

# x and y given as DataFrame columns
import plotly.express as px
df = px.data.iris() # iris is a pandas DataFrame
fig = px.scatter(df, x="sepal_width", y="sepal_length")
fig.show()

我尝试添加 colour = 'red' 等不起作用.这些示例仅向您展示如何通过其他变量进行着色.

I've tried adding colour = 'red' etc doesn't work. These examples only show you how to colour by some other variable.

原则上我可以添加另一个功能并将其设置为相同,但这似乎是完成任务的一种奇怪的方式......

In principle I could add another feature and set it all the same but that seems a bizzare way of accomplishing the task....


解决方案

为此,您可以使用 color_discrete_sequence 参数.

For that you may use the color_discrete_sequence argument.

fig = px.scatter(df, x="sepal_width", y="sepal_length", color_discrete_sequence=['red'])

这个参数是为离散的 color 因素使用自定义调色板,但如果你没有为 color 使用任何因素,它将使用第一个元素情节中的点.

This argument is to use a custom color paletter for discrete color factors, but if you are not using any factor for color it will use the first element for all the points in the plot.

关于离散调色板的更多信息:https://plotly.com/python/discrete-color/

More about discrete color palletes: https://plotly.com/python/discrete-color/

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