sql like 运算符仅获取数字

2022-01-17 00:00:00 numbers sql sql-server

这是我认为一个简单的问题，但还没有得到解决方案.我想仅从此处说明的列中获取有效数字.

This is I think a simple problem but not getting the solution yet. I would like to get the valid numbers only from a column as explained here.

假设我们有一个具有以下值的 varchar 列

Lets say we have a varchar column with following values

ABC
Italy
Apple
234.62
2:234:43:22
France
6435.23
2
Lions

这里的问题是只选择数字

Here the problem is to select numbers only

select * from tbl where answer like '%[0-9]%' 本来可以，但它会返回

select * from tbl where answer like '%[0-9]%' would have done it but it returns 

    234.62
    2:234:43:22
    6435.23
    2

显然，这里不需要 2:234:43:22，因为它不是有效数字.

Here, obviously, 2:234:43:22 is not desired as it is not valid number.

想要的结果是

        234.62
        6435.23
        2

有没有办法做到这一点?

Is there a way to do this?

推荐答案

你可以试试这个

ISNUMERIC (Transact-SQL)

ISNUMERIC 在输入时返回 1表达式计算为有效数字数据类型；否则它返回 0.

ISNUMERIC returns 1 when the input expression evaluates to a valid numeric data type; otherwise it returns 0.

DECLARE @Table TABLE(
        Col VARCHAR(50)
)

INSERT INTO @Table SELECT 'ABC' 
INSERT INTO @Table SELECT 'Italy' 
INSERT INTO @Table SELECT 'Apple' 
INSERT INTO @Table SELECT '234.62' 
INSERT INTO @Table SELECT '2:234:43:22' 
INSERT INTO @Table SELECT 'France' 
INSERT INTO @Table SELECT '6435.23'
INSERT INTO @Table SELECT '2' 
INSERT INTO @Table SELECT 'Lions'

SELECT  *
FROM    @Table
WHERE   ISNUMERIC(Col) = 1

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