MS-SQL 按降序排序输出
我有这个 MS-SQL 查询,数据库中有数千行记录:
I have this MS-SQL query with thousands of row records in database:
SELECT DISTINCT TOP 7 DATENAME(MM, mydatetime) + ' ' + CAST(DAY(mydatetime) AS VARCHAR(2)) as thedate
, MONTH(mydatetime)
, DAY(mydatetime)
, COUNT(Page) as totalcount
, count(DISTINCT Page) as visitors
FROM someTable
WHERE Page LIKE '%AEC%'
GROUP BY DATENAME(MM, mydatetime) + ' ' + CAST(DAY(mydatetime) AS VARCHAR(2))
, MONTH(mydatetime)
, DAY(mydatetime)
ORDER BY MONTH(mydatetime) DESC
, DAY(mydatetime) DESC
它会输出这个:
It will output this:
thedate | totalcount | visitors
-----------------------------------
October 17 | 4 | 1
October 15 | 1 | 1
October 12 | 1 | 1
October 3 | 3 | 3
October 2 | 42 | 22
September 28| 2 | 1
September 21| 14 | 10
我的问题是我根本无法按降序输出,所以它看起来像这样:
My problem is that I simply cant output this in descending order so it will look like this:
thedate | totalcount | visitors
-----------------------------------
September 21| 14 | 10
September 28| 2 | 1
October 2 | 42 | 22
October 3 | 3 | 3
October 12 | 1 | 1
October 15 | 1 | 1
October 17 | 4 | 1
非常感谢任何帮助.
推荐答案
对于您的实际需求,您可以将当前查询用作派生表并按照您想要的方式排序:
For your actual requirement, you can use your current query as a derived table and order that result in the way you want:
SELECT *
FROM ( SELECT DISTINCT TOP 7 DATENAME(mm, mydatetime) + ' '
+ CAST(DAY(mydatetime) AS VARCHAR(2)) AS thedate,
MONTH(mydatetime) AS theMonth,
DAY(mydatetime) AS theDay,
COUNT(page) AS totalcount,
COUNT(DISTINCT page) AS visitors
FROM sometable
WHERE page LIKE '%AEC%'
GROUP BY DATENAME(mm, mydatetime) + ' '
+ CAST(DAY(mydatetime) AS VARCHAR(2)),
MONTH(mydatetime),
DAY(mydatetime)
ORDER BY MONTH(mydatetime) DESC,
DAY(mydatetime) DESC) A
ORDER BY theMonth, theDay
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