需要使用sql developer在oracle db上按日期计算记录和分组计数
我有一张像下面这样的表格
I have a table like the following
ID created sent type
-----------------------------------------------------
0001463583000051783 31-JUL-12 1 270
0081289563000051788 01-AUG-12 1 270
0081289563000051792 01-AUG-12 1 270
0081289563000051791 01-AUG-12 1 270
0081289563000051806 01-AUG-12 1 270
0001421999000051824 06-AUG-12 1 270
0001421999000051826 06-AUG-12 1 270
0001464485000051828 06-AUG-12 1 270
0082162128000051862 09-AUG-12 2 278
0082162128000051861 09-AUG-12 2 278
0022409222082910259 09-AUG-12 3 278
我想要以下输出
created Count
---------------------
31-JUL-12 1
01-AUG-12 4
06-AUG-12 3
09-AUG-12 3
在 Oracle 10g 上使用 SQL Developer 实现这一目标有多难
How hard would it be to accomplish this using SQL Developer on Oracle 10g
我尝试了几次查询来生成这样的表，但最终它没有按日期对计数进行分组，当我们每天平均处理 5000-10000 笔交易时，它只是给我一个1"的计数.我可能把它复杂化了.但我想要一些简单的东西，我可以在一个日期范围内每天提取交易量.
I have tried several queries to generate such a table and in the end it does not group the count by date just gives me a '1' for the count when we average 5000-10000 transactions daily. Im probably over complicating it. But i would like something simple where i can pull the amount of transactions on a daily basis within a date range.
当我运行查询时当前发生的事情是
what is happening currently when i run my queries is
created Count
---------------------
31-JUL-12 1
01-AUG-12 1
01-AUG-12 1
01-AUG-12 1
01-AUG-12 1
06-AUG-12 1
06-AUG-12 1
06-AUG-12 1
09-AUG-12 1
09-AUG-12 1
09-AUG-12 1
推荐答案
我设法通过这个查询获得了这个结果:
I managed to get this results with this query:
select trunc(created), count(*)
from table1
group by trunc(created)
注意trunc函数，即使你不显示它，DATE数据类型也保存时间
Note the trunc function, even if you don't display it, the DATE datatype holds the time as well
这里是一把小提琴
相关文章