SQL Server MERGE 语句的问题
源表
Id, Name, Address
1 A #202
1 A #203
1 A #204
2 A #202
目标表
Id, Name, Address
1 A NULL
合并后
Id, Name, Address
1 A #202
2 A #202
我正在使用这个 SQL
I am using this SQL
create table #S (ID int, Name varchar(25) NULL, Address varchar(25) NULL)
create table #T (ID int, Name varchar(25) NULL, Address varchar(25) NULL)
INSERT #S values(1, 'A', '#202')
INSERT #S values(1, 'A', '#203')
INSERT #S values(1, 'A', '#203')
INSERT #S values(1, 'A', '#204')
INSERT #T values(1, 'A', NULL)
MERGE #T USING
(
Select id, name, address
from #S
) AS S(id,name,address)
on #T.id=S.id and #T.Name=S.Name
when not matched THEN
INSERT values(S.id,S.Name, S.Address)
when matched then
update set Address = S.Address;
GO
Select * from #T
GO
Select * from #S
GO
这会导致错误
消息 8672,级别 16,状态 1,第 18 行
MERGE 语句多次尝试更新或删除同一行.当目标行匹配多个源行时会发生这种情况.MERGE 语句不能多次更新/删除目标表的同一行.细化 ON 子句以确保目标行最多匹配一个源行,或者使用 GROUP BY 子句对源行进行分组.
Msg 8672, Level 16, State 1, Line 18
The MERGE statement attempted to UPDATE or DELETE the same row more than once. This happens when a target row matches more than one source row. A MERGE statement cannot UPDATE/DELETE the same row of the target table multiple times. Refine the ON clause to ensure a target row matches at most one source row, or use the GROUP BY clause to group the source rows.
我想用来自三个匹配值中的任何一个的地址值更新 A 中的行.如何做到这一点?
I want to update the row in A with Address value from any of the three matching values. How to do this?
推荐答案
#S
中的四个值中的任何一个都将匹配目标表的单行值(#S 中的所有值都具有 id = 1和 name = 'A' - 所以它们都匹配目标中的单行),因此这个值将更新四次 - 这就是错误所说的,这是绝对正确的.
Any of the four values in #S
will match your target table's single row value (all values in #S have id = 1 and name = 'A' - so they all match the single row in the target), thus this value will be updated four times - that's what the error says, and it's absolutely right.
你真正想在这里实现什么??
What is it you really want to achieve here??
是否要将地址设置为源表中的第一个值?在您的子选择中使用 TOP 1
子句:
Do you want to set the Address to the first of the values from the source table? Use a TOP 1
clause in your subselect:
MERGE #T
USING (SELECT TOP 1 id, name, address FROM #S) AS S
ON #T.id = S.id AND #T.Name = S.Name
WHEN NOT MATCHED THEN
INSERT VALUES(S.id,S.Name, S.Address)
WHEN MATCHED THEN
UPDATE SET Address = S.Address;
是否要将地址设置为源表中值的随机元素?在您的子选择中使用 TOP 1
和 ORDER BY NEWID()
子句:
Do you want to set the Address to a random element of the values from the source table? Use a TOP 1
and ORDER BY NEWID()
clause in your subselect:
MERGE #T
USING (SELECT TOP 1 id, name, address FROM #S ORDER BY NEWID()) AS S
ON #T.id = S.id AND #T.Name = S.Name
WHEN NOT MATCHED THEN
INSERT VALUES(S.id,S.Name, S.Address)
WHEN MATCHED THEN
UPDATE SET Address = S.Address;
如果您将四个源行与一个目标行相匹配,您将永远不会得到有用的结果 - 您需要知道您真正想要什么.
If you match four source rows to a single target row, you'll never get a useful result - you need to know what you really want.
马克
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