FileNotFoundError: [Errno 2] 没有这样的文件或目录

2022-01-20 00:00:00 python file find

问题描述

我正在尝试打开一个 CSV 文件，但由于某种原因 python 无法找到它.

I am trying to open a CSV file but for some reason python cannot locate it.

这是我的代码(这只是一个简单的代码，但我无法解决问题):

Here is my code (it's just a simple code but I cannot solve the problem):

import csv

with open('address.csv','r') as f:
    reader = csv.reader(f)
    for row in reader:
        print row

解决方案

当你打开一个名为 address.csv 的文件时，你是在告诉 open()您的文件在当前工作目录中的功能.这称为相对路径.

When you open a file with the name address.csv, you are telling the open() function that your file is in the current working directory. This is called a relative path.

为了让您了解这意味着什么，请将其添加到您的代码中:

To give you an idea of what that means, add this to your code:

import os

cwd = os.getcwd()  # Get the current working directory (cwd)
files = os.listdir(cwd)  # Get all the files in that directory
print("Files in %r: %s" % (cwd, files))

这将打印当前工作目录以及其中的所有文件.

That will print the current working directory along with all the files in it.

告诉 open() 函数的另一种方法是使用绝对路径，例如:

Another way to tell the open() function where your file is located is by using an absolute path, e.g.:

f = open("/Users/foo/address.csv")

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