MySQL加入不存在的地方
我有一个连接两个表的 MySQL 查询
I have a MySQL query that joins two tables
- 选民
- 家庭
他们加入 voters.household_id
和 household.id
.
现在我需要做的是修改它,将选民表连接到第三个称为消除的表,沿着 voter.id
和 elimination.voter_id
.然而,问题是我想排除投票者表中在消除表中有相应记录的任何记录.
Now what I need to do is to modify it where the voter table is joined to a third table called elimination, along voter.id
and elimination.voter_id
. However the catch is that I want to exclude any records in the voter table that have a corresponding record in the elimination table.
我如何制作查询来执行此操作?
How do I craft a query to do this?
这是我当前的查询:
SELECT `voter`.`ID`, `voter`.`Last_Name`, `voter`.`First_Name`,
`voter`.`Middle_Name`, `voter`.`Age`, `voter`.`Sex`,
`voter`.`Party`, `voter`.`Demo`, `voter`.`PV`,
`household`.`Address`, `household`.`City`, `household`.`Zip`
FROM (`voter`)
JOIN `household` ON `voter`.`House_ID`=`household`.`id`
WHERE `CT` = '5'
AND `Precnum` = 'CTY3'
AND `Last_Name` LIKE '%Cumbee%'
AND `First_Name` LIKE '%John%'
ORDER BY `Last_Name` ASC
LIMIT 30
推荐答案
我可能会使用 LEFT JOIN
,即使没有匹配也会返回行,然后你可以只选择通过检查 NULL
s 没有匹配的行.
I'd probably use a LEFT JOIN
, which will return rows even if there's no match, and then you can select only the rows with no match by checking for NULL
s.
所以,例如:
SELECT V.*
FROM voter V LEFT JOIN elimination E ON V.id = E.voter_id
WHERE E.voter_id IS NULL
这是否比使用子查询的效率更高或更低取决于优化、索引、每个选民是否可能有不止一个淘汰,等等.
Whether that's more or less efficient than using a subquery depends on optimization, indexes, whether its possible to have more than one elimination per voter, etc.
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