更新表中每一行的一列 [PL/SQL,unix 脚本]
我有一个 12 列的表格:
i have a table with 12 columns:
表 1:
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
---|---|---|---|---|---|---|---|---|---|---|---|
ABC | 1 | 000 | aaa | zzz | 2 | 234 | 哦哦 | 00001 | 01 | 123 | 214 |
定义 | 2 | 023 | bbb | yyy | 4 | 345 | PPP | 00002 | 02 | 133 | 224 |
你好 | 3 | 011 | 抄送 | xxx | 6 | 456 | 00003 | 03 | 143 | 234 | |
jkl | 4 | 112 | ddd | www | 8 | 567 | RRR | 00004 | 04 | 153 | 244 |
我想在循环中使用第三列数据并从另一个表中获取最佳匹配"数据.
i would like to use 3rd column data in a loop and fetch 'best match' data from another table.
表 2:
1 | 2 | 3 | 4 |
---|---|---|---|
0 | 777 | 676 | 美国 |
00 | 888 | 878 | 英国 |
01 | 999 | 989 | 法国 |
02 | 666 | 656 | 德国 |
将在循环中修剪第三列数据,直到获取 table2 中的匹配项.
3rd column data will be trimmed in the loop until a match in table2 is fetched.
first row:
iter 1: table1 row1 col3=000 -- no match in table
iter 2: table1 row1 col3=00 -- return england, replace table1 row1 col12=214 with 'england'
updated row: abc,1,000,aaa,zzz,2,234,OOO,00001,01,123,england
second row:
iter 1: table1 row2 col3=023 -- no match in table
iter 2: table1 row2 col3=02 -- return germany, replace table1 row1 col12=224 with 'germany'
updated row: def,2,023,bbb,yyy,4,345,PPP,00002,02,133,germany
推荐答案
您需要做的是创建一个过程,然后在该过程中声明一个 cursor 以及 variable_c_row cursor_name%ROWTYPE
.
What you will need to do is create a procedure, then within the procedure declare a cursor as well as a variable_c_row cursor_name%ROWTYPE
.
在程序中,这将是内容:
Within the procedure, this will be the contents:
OPEN cursor_name
FETCH cursor_name INTO variable_c_row;
WHILE cursor_name%FOUND LOOP
-- Declare a number variable (i)
i := 0;
-- Declare a varchar variable (match)
match := variable_c_row.col3
WHILE length(match) > 0 LOOP OR l_countryname IS NULL
begin
-- Declare a yourrow%ROWTYPE variable (l_countryname)
SELECT col4 FROM table2 INTO l_countryname WHERE col1 = match;
UPDATE table1 SET col12 = l_countryname;
exception when no_data_found then null;
end;
i := i+1;
match := substr(variable_c_row.cow3, 0, length(match)-i);
END LOOP;
FETCH cursor_name INTO variable_c_row;
END LOOP;
CLOSE cursor_name;
由于问题没有 DDL 或 DML,我最多只能提供一个广泛的答案,尚未经过测试.
Since the question had no DDL or DML, the most I can provide is a broad answer, which has not been tested.
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